$\begin{aligned}
& \text { Actual means }=\mu=\frac{100(40)-50+40}{100} \
& \mu=40-\frac{1}{10}=39.9
\end{aligned}$
Incorrect variance
(5.1)2=100∑xi2−(x)2∑xi2=100×(402)+100(5.1)2∑xi2=16×104+(5.1)2×100=162601σ2=100∑xi2−502+402−(μ)2σ2=1617.01−(39.9)2=25σ=510(μ+σ)=10(39.9+5)=10×44.9=449