$P(\text{exactly 2 heads}) = \binom{3}{2}\left(\frac{1}{2}\right)^3 = \frac{3}{8}$
JEE Main 2025 — Mathematics Probability & Statistics
Verified 30 May 2026.
Question
Three coins are tossed simultaneously. The probability of getting exactly two heads is:
Options
- A
$\frac{3}{8}$
- B
$\frac{1}{8}$
- C
$\frac{1}{2}$
- D
$\frac{1}{4}$
Solution
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