Given set is 0,1,2,3,...,10.
So, total number of outcomes are (11×11)=121
Favourable outcomes are:
(0,6),(0,7),(0,8),(0,9),(0,10),(1,7),(1,8),(1,9),(1,10),(2,8),(2,9),(2,10),(3,9),(3,10),(4,10)
And the same number of elements when xandy are interchanged.
So, the number of favourable outcomes are 30.
So, the required probability is given by P(E)=12130.