a,b,c∈Na<b<c x= mean =59+25+a+b+c=18 a+b+c=56 Mean deviation =nΣ∣xi−x∣=4 =9+7+∣18−a∣+∣18−b∣+∣18−c∣=20=∣18−a∣+∣18−b∣+∣18−c∣=4 Variance =nΣ∣xi−x∣2=5136 =81+49+∣18−a∣2+∣18−b∣2+∣18−c∣2=136=(18−a)2+(18−b)2+(18−c)2=6 Possible values (18−a)2=1,(18−b)2=1(18−c)2=4 a<b<c so 18−a=1a=1718−b=−1 b=1918−c=−2c=20 a+b+c=56 2a+b−c34=19−20=33