$\begin{array}{|l|c|c|}
\hline & \text{A} & \text{B} \
\hline \text{Manufactured} & 60 % & 40 % \
\hline \text{Standard quality} & 80 % & 90 % \
\hline
\end{array}\mathrm{P}(Manufacturedat\mathrm{B} /foundstandardquality)=?A:FoundS.QB:ManufactureB\mathrm{C}:ManufactureA\begin{aligned}
& P\left(E_1\right)=\frac{40}{100} \
& P\left(E_2\right)=\frac{60}{100} \
& P\left(A / E_1\right)=\frac{90}{100} \
& P\left(A / E_2\right)=\frac{80}{100} \
& \because P\left(E_1 / A\right)=\frac{P\left(A / E_1\right) P\left(E_1\right)}{P\left(A / E_1\right) P\left(E_1\right)+P\left(A / E_2\right) P\left(E_2\right)}=\frac{3}{7} \
& \therefore 126 P=54
\end{aligned}$