Using Bayes' theorem:
P(k=1∣all black)=P(all black)P(all black∣k=1)⋅P(k=1) where P(k)=111 for each k∈{0,1,...,10}.
When k=1: P(all 3 black∣k=1)=(310)(39)=12084=107.
Calculating P(all black)=111k=0∑10120(310−k).
Numerator is 120+84+56+35+20+10+4+1=330.
So P(all black)=111⋅120330=41.
Therefore P(k=1∣all black)=41107⋅111=107⋅114=11028=5514