Let the two observations be a and b.
Given:
Mean=5
⇒51+3+5+a+b=5
⇒a+b=16…(1)
And
σ2=5∑xi2−(5∑xi)2
⇒8=512+32+52+a2+b2−25
⇒a2+b2=130…(2)
Solving (1)&(2), we get
(16−b)2+b2=130
⇒b=9
So a=7
Hence, a3+b3=343+729=1072
The mean and variance of 5 observations are 5 and 8 respectively. If 3 observations are 1,3,5, then the sum of cubes of the remaining two observations is
Held on 1 Feb 2023 · Verified 6 Jul 2026.
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