Let a1=a and common difference be d.
Now,
a1+a3=10
⇒2a+2d=10
⇒a+d=5...(i)
Now,
Given mean xˉ=219
⇒6a+(a+d)+(a+2d)+...+(a+5d)=219
⇒66a+15d=219
⇒2a+5d=19...(ii)
Solving (i)&(\mathrm{ii}), we get
a=2,d=3
So, A.P is 2,5,8,11,14,17.
Now variance is given by,
σ2=61i=1∑6xi−(xˉ)2
⇒σ2=64+25+64+121+196+289−(219)2
⇒σ2=6699−4361
⇒σ2=4105
⇒8σ2=210