Given,
a1 be any natural number
So, a1,a1+1,a1+2,….,a1+99 are values of ai or observation.
Now mean of the observation is given by,
xˉ=100a1+(a1+1)+(a1+2)+….+a1+99
⇒xˉ=100100a1+(1+2+…..+99)
⇒xˉ=a1+2×10099×100
⇒xˉ=a1+299
Mean deviation about mean=100∑i=1100∣xi−xˉ∣
=1002(299+297+295+….+21)
=1001+3+….+99
=100250[1+99]
=25
So, it is true for every natural no. ' a1 ' as there is no term of a1 in mean deviation.