We have,
| xi | fi | di=xi−5 | fidi2 | fidi |
| 2 | 3 | −3 | 27 | −9 |
| 3 | 6 | −2 | 24 | −12 |
| 4 | 16 | −1 | 16 | −16 |
| 5 | α | 0 | 0 | 0 |
| 6 | 9 | 1 | 9 | 9 |
| 7 | 5 | 2 | 20 | 10 |
| 8 | 6 | 3 | 54 | 18 |
σx2=σd2=∑fi∑fidi2−(∑fi∑fidi)2
⇒3=45+α150−0
⇒150=135+3α
⇒3α=15⇒α=5
If the variance of the frequency distribution
| xi | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| Frequency fi | 3 | 6 | 16 | α | 9 | 5 | 6 |
Held on 31 Jan 2023 · Verified 6 Jul 2026.
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