Given that the mean for the frequency distribution is 28.
We know that Mean (x)=∑fi∑fixi
Now for the class interval 0−10 we get x1=20+10=5.
Similarly we can calculate xi for other class intervals.
Now we know that mean =28
⇒14+x2×5+3×15+x×25+5×35+4×45=28
⇒x=6
Also we know that variance (σ2)=∑fi∑fi(xˉ−xi)2
σ2=202×(28−5)2+3×(28−15)2+6×(28−25)2+5×(28−35)2+4×(28−45)2
σ2=202×(23)2+3×(13)2+6×(3)2+5×(7)2+4×(17)2
σ2=151
Hence this is the required answer.