Given,
The mean and variance of the frequency distribution
| xi | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
| fi | 4 | 4 | α | 15 | 8 | β | 4 | 5 |
are
9 and
15.08 respectively,
Now mean is given by,
Mean =40+α+β8+16+120+80+56+80+6α+12β=9
⇒360+9α+9β=360+6α+12β
⇒3α−3β=0
⇒α=β......(1)
Now variance is given by,
15.08=40+2α16+64+36α+960+800+144α+784+1280−92
⇒96.08=40+2α3904+180α
⇒(40+2α)(96.08)=3904+180α
⇒3843.20+(192.16)α=3904+180α
⇒(12.16)α=60.80
⇒α=5=β
Hence, α2+β2−αβ=25+25−25=25