It is given that P(H)=3P(T)
∴P(H)=43,P(T)=41
Since coin is tossed till either 1H or 3T occurs. So, process will end in the maximum of 3 throws.
| Xi | 1 | 2 | 3 |
| P(Xi) | 43 | 41⋅43 | 41×41×41+41×41×43 |
Now we know that,
Mean is given by i=1∑nXiP(Xi)
Mean=1×43+2×163+3×161=1621
Hence, this is the correct option.