Total No of 3-digit Number =900
Case -1 When there are 2 odd digit and 1 even digit
(i) Even odd odd =4×5×5=100
{As 0 cannot come at 1st place}
(ii) Odd even odd =5×5×5=125
(iii) Odd odd even =5×5×5=125
Case-2
All 3 odd digit =5×5×5=125
So total number of selecting 3-digit number having atleast 2 odd digit will be addition of both cases which is=100+125+125+125=475
So probability =900475=3619