Calculating Mean =53+7+12+a+43−a=13
Variance =59+49+144+a2+(43−a)2−132∈N
⇒52a2−a+1=n (where n∈N)
⇒2a2−a+1−5n=0 must have solution as natural numbers
So, D=40n−7 always has 3 at unit place for any value of n
⇒D can't be perfect square
So, a can't be integer.