Given,
Wrong mean =μ1=30
Wrong standard deviation =σ1=5
Now mean ig given by 40∑xi=30
⇒∑xi=1200
Variance is given by σ12=25
⇒40∑xi2−302=25
⇒∑xi2=925×40=37000
New sum of mean =∑xi′=1200−10−12=1178
So, new mean =μ1′=381178=31
Now new variance ∑xi2=37000−(10)2−(12)2=36756
So, new S.D. σ1′=3836756−(31)2=σ
36756−(31)2×38=38σ2
⇒38σ2=238