Given, five-digit number,
So n(S)=total 5 digit number will be=9×104
Now let A: number is multiple of 7 but not divisible by 5
Smallest 5 digit divisible by 7 is 10003
Largest 5 digit divisible by 7 is 99995
Now by using nth term of A.P formula we have,
∴99995=10003+(n−1)7
⇒n=12857
Now finding number which is divisible by 35
Again using A.P formula we have,
99995=10010+(P−1)35
⇒P=2572
Now number divisible by 7 but not by 35 are
12857−2572=10285
So, probability will be P=9000010285
And 9P=1.0285