$P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.2}{0.5} = 0.4$
JEE Main 2022 — Mathematics Probability & Statistics
Verified 30 May 2026.
Question
If $P(A) = 0.4$, $P(B) = 0.5$, and $P(A \cap B) = 0.2$, then $P(A|B)$ is:
Options
- A
$0.4$
- B
$0.5$
- C
$0.8$
- D
$0.25$
Solution
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