We know that mean deviation about the mean of odd natural number is given by M.D (x)=n1[4n2−1]
So, now n1[4n2−1]=n5(n+1) (given)
⇒n−1=20⇒n=21
If the mean deviation about the mean of the numbers 1,2,3,……,n, where n is odd, is n5(n+1), then n is equal to ______.
Held on 25 Jun 2022 · Verified 6 Jul 2026.
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