n(S)=36
The possible ordered pairs are (1,1),(1,2),(1,3),(1,5),(1,7),(2,1),(2,2),(2,3),(2,5),(3,1),(3,2),(3,3),(3,5),(5,1)(5,2),(5,3),(7,1)
n(E)=5+4+4+3+1=17
So, P(E)=3617
JEE Main 2021 — Mathematics Probability & Statistics
Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11, then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:
Held on 17 Mar 2021 · Verified 6 Jul 2026.
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3617
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21
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