ΣP(X)=1
⇒K+2K+2K+3K+K=1
K=91
P=P(1<X<4∣X<3)=P(X<3)P(X=2)
P=9KK+9K2k9K2K=32
5P=λK
5×32=λ×91⇒λ=30
The probability distribution of random variable X is given by:
| X | 1 | 2 | 3 | 4 | 5 |
| P(X) | K | 2K | 2K | 3K | K |
Held on 27 Aug 2021 · Verified 6 Jul 2026.
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