Given that
7,10,13--&8,10,12,---\in A.P
rthterm of an A.P⇒tr=a+(r−1)d
Here a=7,d=3&a=8,d=2
{t}_{r}=3r+4&{t}_{r}=2r+6
r=1∑10(3r+4)(2r+6)
=r=1∑10(6r2+26r+24)=6r=1∑10r2+26r=1∑10r+r=1∑1024
r=1∑n1=n,r=1∑nr=2n(n+1),r=1∑nr2=6n(n+1)(2n+1),r=1∑nr3=[2n(n+1)]2
=6(610×11×21)+26(210×11)+24(10)
=2310+1430+240=3980
mean =398