Given
| x: | x1=2 | x2=6 | x3=8 | x4=9 | Total |
| f: | 4 | 4 | α | β | 8+α+β |
| fx: | 8 | 24 | 8α | 9β | 32+8α+9β |
| f(x−x)2: | 64 | 0 | 4α | 9β | 64+4α+9β |
x=∑i=14fi∑i=14fixi
32+8α+9β=(8+α+β)×6
⇒2α+3β=16...(1)
Also, for the variance, \displaystyle {\sigma }^{2}=\frac{\sum {f}_{i}{({x}_{i}-x)}^{2}_{i=1}^{4}}{\sum {f}_{i}_{i=1}^{4}}
64+4α+9β=(8+α+β)×6.8
⇒640+40α+90β=544+68α+68β
⇒28α−22β=96
⇒14α−11β=48...(2)
from (1)&(2)
\alpha =5&\beta =2
so, new mean =1532+35+18=1585=317