Let observations are denoted by xi for 1≤i<2n
xˉ=2n∑xi=2n(a+a+…+a)−(a+a+…+a)
⇒xˉ=0
and σx2=2n∑xi2−(xˉ)2=2na2+a2+…+a2−0=a2
⇒σx=a
Now, adding a constant b then yˉ=xˉ+b=5
⇒b=5
and σy=σx (No change in S.D.) ⇒a=20
⇒a2+b2=425
JEE Main 2021 — Mathematics Probability & Statistics
Let in a series of 2n observations, half of them are equal to a and remaining half are equal to −a. Also by adding a constant b in each of these observations, the mean and standard deviation of new set become 5 and 20, respectively. Then the value of a2+b2 is equal to :
Held on 18 Mar 2021 · Verified 6 Jul 2026.
425
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250
925
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