Given:
Mean=10
⇒67+10+11+15+a+b=10
⇒a+b=17…(i)
And,
Variance=320
⇒672+102+112+152+a2+b2−102=320
⇒6495+a2+b2=3320
⇒495+a2+b2=640
⇒a2+b2=145…(ii)
Solve (i) and (ii), we get
a=9,b=8 or a=8,b=9
∴∣a−b∣=1
If the mean and variance of six observations 7,10,11,15,a,b are 10 and 320, respectively, then the value of ∣a−b∣ is equal to:
Held on 20 Jul 2021 · Verified 6 Jul 2026.
9
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