∵ Sum of frequencies =584
α+110+54+30+β=584
⇒α+β=390...(1)
Now, Median is at 2584=292th term
∵ Median =45 (lies in class 40−50)
⇒α+110+54+15=292
⇒α=113...(2)
On solving, equations (1) and(2), we get
\Rightarrow \alpha =113&\beta =390-113=277
⇒∣α−β∣=164