P((E2C∩E3C)/E1)=P(E1)P(E1∩(E2C∩E3C))
=P(E1)P(E1)−P(E1∩E2)+P(E1∩E3)−P(E1∩E2∩E3)
=P(E1)P(E1)−P(E1∩E2)−P(E1∩E3)−0
=1−P(E1)P(E1∩E2)−P(E1)P(E1∩E3)=1−P(E2/E1)−P(E3/E1)
=1−P(E2)−P(E3)
=P(E3C)−P(E2) or P(E2C)−P(E3)
JEE Main 2020 — Mathematics Probability & Statistics
Let EC denote the complement of an event E. Let E1,E2 and E3 be any pairwise independent events with P(E1)>0 and P(E1∩E2∩E3)=0 then P((E2C∩E3C)/E1) is equal to
Held on 2 Sept 2020 · Verified 6 Jul 2026.
P(E2C)+P(E3)
P(E3C)−P(E2C)
P(E3)−P(E2C)
P(E3C)−P(E2)
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