$P(\text{at least one 6}) = 1 - P(\text{no 6 in any throw})$
$$= 1 - \left(\frac{5}{6}\right)^6$$
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JEE Main 2020 — Mathematics Probability & Statistics
medium
mcq
2020
Official previous-year question
Verified 30 May 2026.
Question
A die is thrown $6$ times. The probability of getting at least one six is:
Options
- A
$1 - \left(\frac{5}{6}\right)^6$
- B
$\left(\frac{1}{6}\right)^6$
- C
$1 - \left(\frac{1}{6}\right)^6$
- D
$6 \cdot \frac{1}{6}$
Solution
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