Let the remaining two observations are x and y.
Mean xˉ=N∑xi=72+4+10+12+14+x+y
⇒742+x+y=8
⇒x+y=14...(1)
Variance,
σ2=N∑xi2−(xˉ)2=74+16+100+144+196+x2+y2−64
⇒σ2=7460+x2+y2−64=16
⇒x2+y2=100…(2)
From (1) and (2), we get,
x=6, y=8 and xy=48
JEE Main 2019 — Mathematics Probability & Statistics
The mean and variance for seven observations are 8 and 16 respectively. If 5 of the observations are 2,4,10,12,14, then the product of the remaining two observations is
Held on 8 Apr 2019 · Verified 6 Jul 2026.
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