P(hittingtarget)=31
Let number of trials =n
P(hittingtargetatleastonce)
=1−P (nothit)
=1−(32)n>65
⇒(61)>(32)n
So minimum number of trials =5
If the probability of hitting a target by a shooter, in any shot is 31, then the minimum number of independent shots at the target required by him so that the probability of hitting the target at least once is greater than 65, is:
Held on 10 Jan 2019 · Verified 6 Jul 2026.
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