Let the numbers are x1,x2,…x10(N=10)
Given \displaystyle \begin{matrix}{x}_{1}+{x}_{2}+{x}_{3}+{x}_{4}=4.11=44 \\ {x}_{5}+{x}_{6}\ldots .+{x}_{10}=6.16=96\end{matrix}}\Rightarrow \sum {x}_{i}=140
⇒ variance σ2=N∑xi2−(N∑xi)2
⇒σ2=102000−(10140)2
⇒σ2=200−196=4
⇒ Standard deviation σ=2.