xˉ=n∑xi=9
s.d=∑n(xi−xˉ)2=0
⇒xi=xˉ∀i
∴ each term in the original observation is 9
⇒ observation 1=9,9,9,9,9
xˉnew=n∑xi=59+9+9+9+x5
⇒10=536+x5
⇒x5=14
⇒ new set of observations =9,9,9,9,14
s.dnew=n∑(xi−xˉnew)2
=5(9−10)2+(9−10)2+(9−10)2+(14−10)2
=54+42
=520=2