Given i=1∑10xi=400 and
i=1∑100xi2=2475
Variance of 97 observations=σ2=N∑xi2−(N∑xi)2
(∴3+4+5=12,32+42+52=50)
=972425−(97388)2
=972425−16
=972425−1552=97873
=9
JEE Main 2017 — Mathematics Probability & Statistics
The sum of 100 observations and the sum of their squares are 400&2475, respectively. Later on, three observations 3,4&5 were found to be incorrect. If the incorrect observations are omitted, then the variance of the remaining observations is
Held on 9 Apr 2017 · Verified 6 Jul 2026.
8.25
8.50
9.00
8.00
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