For Bernoulli's trials
Variance =n.p.q
Given, number of trials n=10
Probability of drawing a green ball p=2515=53 and q=52
Hence, Variance =10×53×52=512
A box contains 15 green and 10 yellow balls. If 10 balls are randomly drawn, one-by-one, with replacement, then the variance of the number of green balls drawn is:
Held on 2 Apr 2017 · Verified 6 Jul 2026.
512
6
4
256
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