E1→A show up 4
E2→B shows up 2
E3→ Sum is odd (i.e., even + odd or odd + even)
P(E1)=6.66=61
P(E2)=6.66=61
P(E3)=6.63.3+6.63.3=42=21
P(E1∩E2)=6.61=P(E1).P(E2)
⇒ {E}_{1} & {E}_{2} are independent
P(E1∩E3)=6.61.3=P(E1).P(E3)
⇒ {E}_{1} & {E}_{3} are independent
P(E2∩E3)=6.61.3=121=P(E2).P(E3)
⇒ {E}_{2}& {E}_{3} are independent
P(E1∩E2∩E3)=0 =P(E1)×P(E2)×P(E3)