Given (x−30)(x−10)(x−50)≥0 Let x≥10,x≥50 equation will be true ∀x≥50 as (x−30x−50)≥0,∀x∈[10,30) x−30(x−10)(x−50)≥0∀x∈[10,30) Total value of x between 10 to 30 is 20 . Total values of x between 50 to 100 including 50 and 100 is 51 . Total values of x=51+20=71 P( A)=10071=0.71