⇒⇒⇒52+53×52+(53)2×52+……+(53)k⋅52>10752[1+53+(53)2+……+(53)k]>10752×1−531−(53)k>107⇒1−(53)k>107(53)k<103⇒k≥3 Hence minimum value of k=3
JEE Main 2013 — Mathematics Probability & Statistics
The probability of a man hitting a target is 52. He fires at the target k times (k, a given number). Then the minimum k, so that the probability of hitting the target at least once is more than 107, is :
Held on 9 Apr 2013 · Verified 6 Jul 2026.
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