Let A be the event that maximum is 6. B be event that minimum is 3 P(A)=8C35C2 (the numbers <6 are 5) P(B)=8C35C2 (the numbers >3 are 5) P(A∩B)=8C32C1 Required probability is P(AB)=P(A)P(A∩B)=5C22C1=102=51.
Three numbers are chosen at random without replacement from 1,2,3, … . .8. The probability that their minimum is 3 , given that their maximum is 6 ,…
JEE Main 2012 — Mathematics Probability & Statistics
Three numbers are chosen at random without replacement from {1,2,3,…..8}. The probability that their minimum is 3 , given that their maximum is 6 , is
Held on 30 Apr 2012 · Verified 6 Jul 2026.
Options
- A
83
- B
51
- C
41
- D
52
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