∑i=1ni∑i=1ni2=2n(n+1)6n(n+1)(2n+1)=32n+1 For n=1,2,3,…..,1000 Value of 32n+1=33,35,37,………,32001 respectively. Out of 33,35,37,………,32001 only first term (33=1), fourth term (39=3),667th term (32001=667) are integers. Hence, out of 1000 values of 32n+1, total number of integral values of 32n+1 =333+1=334 ∴ Required probability =1000334=0.334