N(S)=20C4 Statement-1: common difference is 1 ; total number of cases =17 common difference is 2 ; total number of cases =14 common difference is 3 ; total number of cases =11 common difference is 4 ; total number of cases =8 common difference is 5 ; total number of cases =5 common difference is 6 ; total number of cases =2 Prob. =20C417+14+11+8+5+2=851.
Four numbers are chosen at random (without replacement) from the set 1,2,3, … ., 20. Statement-1: The probability that the chosen numbers when…
JEE Main 2010 — Mathematics Probability & Statistics
Four numbers are chosen at random (without replacement) from the set {1,2,3,….,20}. Statement-1: The probability that the chosen numbers when arranged in some order will form an AP is 851. Statement-2: If the four chosen numbers from an AP, then the set of all possible values of common difference is {±1,±2,±3,±4,±5}.
Held on 30 Apr 2010 · Verified 6 Jul 2026.
Options
- A
Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation for Statement-1
- B
Statement-1 is true, Statement-2 is false
- C
Statement-1 is false, Statement-2 is true
- D
Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation for Statement-1
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