Statement-2 is true Statement-1: Sum of n even natural numbers =n(n+1) Mean (xˉ)=nn(n+1)=n+1 Variance =[n1∑(x1)2]−(xˉ)2=n1[22+42+….+(2n)2]−(n+1)2=n122[12+22+….+n2]−(n+1)2=n46n(n+1)(2n+1)−(n+1)2=3(n+1)[2(2n+1)−3(n+1)]=3(n+1)[4n+2−3n−3]=3(n+1)(n−1)=3n2−1 ∴ Statement 1 is false.