P(A∪B)=P(A)+P(B)−P(A∩B)⇒43=1−P(Aˉ)+P(B)−41 ⇒1=1−32+P(B)⇒P(B)=32; Now, P(Aˉ∩B)=P(B)−P(A∩B)=32−41=125
JEE Main 2002 — Mathematics Probability & Statistics
A and B are events such that P(A∪B)=3/4,P(A∩B)=1/4,P(Aˉ)=2/3 then P(Aˉ∩B) is
Held on 30 Apr 2002 · Verified 6 Jul 2026.
5/12
3/8
5/8
1/4
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