Ellipse E: 144x2+169y2=1 has a2=169,b2=144, so cE=25=5 with foci at (0,±5).
Hyperbola H: x2y2−16x2=1 has the same foci, so cH2=x2+16=25, giving x2=9.
Thus H is 9y2−16x2=1 with a=3,b=4,c=5.
Eccentricity: e=35.
Latus rectum: L=a2b2=332.
Therefore 24(e+L)=24(35+332)=24⋅337=296