Skip to main content

Let the eccentricity e of a hyperbola satisfy the equation 6e^2 - 11e + 3 = 0. If the foci of the hyperbola are (3, 5) and (3, -4), then the length…

JEE Main 2026 — Mathematics Coordinate Geometry

2026mcqmedium

Let the eccentricity eee of a hyperbola satisfy the equation 6e2−11e+3=06e^2 - 11e + 3 = 06e2−11e+3=0. If the foci of the hyperbola are (3,5)(3, 5)(3,5) and (3,−4)(3, -4)(3,−4), then the length of its latus rectum is :

Official previous-year question

Held on 5 Apr 2026 · Verified 6 Jul 2026.

Options

  1. A

    113\dfrac{11}{3}311​

  2. B

    173\dfrac{17}{3}317​

  3. C

    152\dfrac{15}{2}215​

  4. D

    172\dfrac{17}{2}217​

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Coordinate Geometry in other years

More JEE Main Coordinate Geometry questions

Other Mathematics topics for JEE Main

Keep practicing Coordinate Geometry

Work through every JEE Main Coordinate Geometry PYQ, year by year.

Browse all Mathematics topics