Using parametric form through P(2,3): point at distance r=32 is (2+rcosθ, 3+rsinθ).
Substituting in x+y=6: r(cosθ+sinθ)=1, so cosθ+sinθ=23.
2sin(θ+4π)=23⇒sin(θ+4π)=23.
θ+4π=3π or 32π.
θ1=12π, θ2=125π.
θ1+θ2=12π+125π=2π.
JEE Main 2026 — Mathematics Coordinate Geometry
Let the angles made with the positive x-axis by two straight lines drawn from the point P(2,3) and meeting the line x+y=6 at a distance 32 from the point P be θ1 and θ2. Then the value of (θ1+θ2) is:
Held on 24 Jan 2026 · Verified 6 Jul 2026.
3π
6π
2π
12π
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