For the ellipse 25x2+9y2=1, we have a=5, b=3, c=4.
So foci are at S(±4,0).
For point P on the ellipse: SP+S′P=10.
Given (SP)2+(S′P)2−SP⋅S′P=37
Let r1=SP and r2=S′P.
From (r1+r2)2=100, we get r12+r22=100−2r1r2.
Substituting into the given equation: 100−3r1r2=37, so r1r2=21.
Thus r1=3,r2=7.
From (α+4)2+β2=9 and (α−4)2+β2=49, subtracting gives 16α=−40, so α=−25.
From the ellipse equation: β2=427.
Therefore α2+β2=425+427=13.