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Let x^2 f(a^2+7a+3) + y^2 f(3a+15) = 1 represent an ellipse with major axis along y-axis, where f is a strictly decreasing positive function on…

JEE Main 2026 — Mathematics Coordinate Geometry

2026mcqmedium

Let x2f(a2+7a+3)+y2f(3a+15)=1\dfrac{x^2}{f(a^2+7a+3)} + \dfrac{y^2}{f(3a+15)} = 1f(a2+7a+3)x2​+f(3a+15)y2​=1 represent an ellipse with major axis along yyy-axis, where fff is a strictly decreasing positive function on R\mathbb{R}R. If the set of all possible values of aaa is R−[α,β]\mathbb{R} - [\alpha, \beta]R−[α,β], then α2+β2\alpha^2+\beta^2α2+β2 is equal to:

Official previous-year question

Held on 8 Apr 2026 · Verified 6 Jul 2026.

Options

  1. A

    282828

  2. B

    404040

  3. C

    616161

  4. D

    242424

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