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Let PQ and MN be two straight lines touching the circle x^2+y^2-4 x-6 y-3=0 at the points A and B respectively. Let O be the centre of the circle and…

JEE Main 2026 — Mathematics Coordinate Geometry

2026mcqmedium

Let PQ and MN be two straight lines touching the circle x2+y2−4x−6y−3=0x^{2}+y^{2}-4 x-6 y-3=0x2+y2−4x−6y−3=0 at the points A and B respectively. Let O be the centre of the circle and ∠AOB=π/3\angle \mathrm{AOB}=\pi / 3∠AOB=π/3. Then the locus of the point of intersection of the lines PQ and MN is :

Official previous-year question

Held on 21 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    x2+y2−12x−18y−25=0x^{2}+y^{2}-12 x-18 y-25=0x2+y2−12x−18y−25=0

  2. B

    3(x2+y2)−18x−12y+25=03\left(x^{2}+y^{2}\right)-18 x-12 y+25=03(x2+y2)−18x−12y+25=0

  3. C

    3(x2+y2)−12x−18y−25=03\left(x^{2}+y^{2}\right)-12 x-18 y-25=03(x2+y2)−12x−18y−25=0

  4. D

    x2+y2−18x−12y−25=0x^{2}+y^{2}-18 x-12 y-25=0x2+y2−18x−12y−25=0

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