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Let P(10,2 √15) be a point on the hyperbola x^2 a^2- y^2 ~b^2=1, whose foci are S and S^prime. If the length of its latus rectum is 8, then the…

JEE Main 2026 — Mathematics Coordinate Geometry

2026mcqmedium

Let P(10,215)\mathrm{P}(10,2 \sqrt{15})P(10,215​) be a point on the hyperbola x2a2−y2 b2=1\frac{x^{2}}{\mathrm{a}^{2}}-\frac{y^{2}}{\mathrm{~b}^{2}}=1a2x2​− b2y2​=1, whose foci are S and S′\mathrm{S}^{\prime}S′. If the length of its latus rectum is 8, then the square of the area of ΔPSS′\Delta \mathrm{PSS}^{\prime}ΔPSS′ is equal to :

Official previous-year question

Held on 22 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    900

  2. B

    4200

  3. C

    1462

  4. D

    2700

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