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Let P be a moving point on the circle x^2 + y^2 - 6x - 8y + 21 = 0. Then, the maximum distance of P from the vertex of the parabola x^2 + 6x + y + 13…

JEE Main 2026 — Mathematics Coordinate Geometry

2026mcqmedium

Let PPP be a moving point on the circle x2+y2−6x−8y+21=0x^2 + y^2 - 6x - 8y + 21 = 0x2+y2−6x−8y+21=0. Then, the maximum distance of PPP from the vertex of the parabola x2+6x+y+13=0x^2 + 6x + y + 13 = 0x2+6x+y+13=0 is equal to:

Official previous-year question

Held on 5 Apr 2026 · Verified 6 Jul 2026.

Options

  1. A

    888

  2. B

    101010

  3. C

    121212

  4. D

    999

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